Definition: Infinity refers to something without any limit, and is a concept relevant in a number of fields, predominantly mathematics and physics. The English word infinity derives from Latin infinitas, which …

Aug 11, 2012 · I know that $\\infty/\\infty$ is not generally defined. However, if we have 2 equal infinities divided by each other, would it be 1? if we have an infinity divided by another half-as-big infinity, for

Apr 28, 2016 · First of all: you cannot just subtract infinity from infinity. Infinity is not a real number so you can't simply use the basic operations as you're used to do with (real) real numbers.

Jun 9, 2023 · so long as x is a finite number. Meaning, adding or subtracting a finite number to an infinity does not change its value, but I vaguely remember a YouTube video that talked about different kinds …

Mar 25, 2011 · To reply to user 3302, Your wrong. lim [as x->0]f (x)=1/x does not exist, if you approach it from the right you get +infinity and if you approach it from the left you get -infinity, therefore your …

Dec 25, 2017 · In the process of investigating a limit, we know that both the numerator and denominator are going to infinity.. but we dont know the behaviour of each dynamics.

Similarly, the reals and the complex numbers each exclude infinity, so arithmetic isn't defined for it. You can extend those sets to include infinity - but then you have to extend the definition of the arithmetic …

Dec 13, 2021 · But I can't disprove their points. My argument is that if $1 + \infty > \infty$ then there exists a number greater than $\infty$, disproving the concept of infinity, because you can't simply add …

May 14, 2017 · The infinity can somehow branch in a peculiar way, but I will not go any deeper here. This is just to show that you can consider far more exotic infinities if you want to. Let us then turn to …

Oct 27, 2016 · There is a general formula for indeterminate form $1 ^ {\\infty}$ which I'm looking for a proof which is also used here. (picture) Given $$\\lim_{x\\to a} f(x) = 1$$ and $$\\lim_{x\\to a} g(x) = …